What was the potential energy of truck 1 at the top of the hill?

February 26th, 2009 | by Michael |
truck
krysdizzle_2006 asked:

You are a researcher of traffic accident. You arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each) were involved in an accident to a post lantern arrest. Here is what you know: The truck 1 approched the intersection from the top of a hill of 22 meters. 2 The truck was on a flat stretch of road directly in front of the truck 1. At the bottom of the hill, before braking for the light stop, the truck 1 was going 20 m / s 2 and the truck was going 35 m / s. From skid marks on the road you can see the force applied on the vehicle 1 brakes on for 2 seconds, 80 meters before stopping lantern. There were skid marks left by truck 2nd The clash appeared to stop the lantern, where the truck was arrested 2. After the collision, both trucks were approaching in the same direction at 10m / s, before slowly rolling to a stop. If you now push truck 2 using 1000 N of force, 8 meters off the side of the road so nobody else gets hurt.

IRVIN
  1. One Response to “What was the potential energy of truck 1 at the top of the hill?”

  2. By Albert on Mar 1, 2009 | Reply

    The gravitational potential energy of the truck at the top of the hill is calculated as mass x gravity x height

    3000 x 9.81 x 22 = 647.46kJ

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