How much energy did truck 1 lose from the top to the bottom of the hill?
March 13th, 2009 | by Michael |
krysdizzle_2006 asked:
You are a researcher of traffic accident. You arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each) were involved in an accident to a post lantern arrest. here? what you know: The truck 1 approched the intersection from the top of a hill of 22 meters. 2 The truck was on a flat stretch of road directly in front of the truck 1. At the bottom of the hill, before braking for the light stop, the truck 1 was going 20 m / s 2 and the truck was going 35 m / s. From skid marks on the road you can see the force applied on the vehicle 1 brakes on for 2 seconds, 80 meters before stopping lantern. There were skid marks left by truck 2nd The clash is? presented to the arrest of the lantern, where the truck was arrested 2. After the collision, both trucks were approaching in the same direction at 10m / s, before slowly rolling to a stop. If you now push truck 2 using 1000 N of force, 8 meters off the side of the road so nobody else gets hurt.
You are a researcher of traffic accident. You arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each) were involved in an accident to a post lantern arrest. here? what you know: The truck 1 approched the intersection from the top of a hill of 22 meters. 2 The truck was on a flat stretch of road directly in front of the truck 1. At the bottom of the hill, before braking for the light stop, the truck 1 was going 20 m / s 2 and the truck was going 35 m / s. From skid marks on the road you can see the force applied on the vehicle 1 brakes on for 2 seconds, 80 meters before stopping lantern. There were skid marks left by truck 2nd The clash is? presented to the arrest of the lantern, where the truck was arrested 2. After the collision, both trucks were approaching in the same direction at 10m / s, before slowly rolling to a stop. If you now push truck 2 using 1000 N of force, 8 meters off the side of the road so nobody else gets hurt.
One Response to “How much energy did truck 1 lose from the top to the bottom of the hill?”
By emsviper on Mar 15, 2009 | Reply
OK — so you want to know the energy? Since you’re going from the top of a hill to its bottom, you know that all of your gravitational potential energy is going to be changed into kinetic energy. Since the truck applied its brakes you know that some of that energy was lost so instead of Ug = KE = mgh = 0.5mv^2 you get Ug = KE - f